tensorflow::ops::Transpose

Shuffle dimensions of x according to a permutation.

Summary

The output y has the same rank as x. The shapes of x and y satisfy: y.shape[i] == x.shape[perm[i]] for i in [0, 1, ..., rank(x) - 1]

Arguments:

• scope: A Scope object

Returns:

• Output: The y tensor.

Public attributes

::tensorflow::Output y

 Transpose(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x,
  ::tensorflow::Input perm
)

::tensorflow::Node * node() const 

 operator::tensorflow::Input() const 

 operator::tensorflow::Output() const