![]() |
Returns True
if any member of v
has an ancestor in ancestor
s.
tfp.experimental.lazybones.utils.is_any_ancestor(
v, ancestor
)
![]() |
Returns True
if any member of v
has an ancestor in ancestor
s.
tfp.experimental.lazybones.utils.is_any_ancestor(
v, ancestor
)
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Last updated 2021-01-06 UTC.