tensorflow::ops::Unique

#include <array_ops.h>

Finds unique elements in a 1-D tensor.

Summary

This operation returns a tensor y containing all of the unique elements of x sorted in the same order that they occur in x. This operation also returns a tensor idx the same size as x that contains the index of each value of x in the unique output y. In other words:

y[idx[i]] = x[i] for i in [0, 1,...,rank(x) - 1]

For example:

```prettyprint tensor 'x' is [1, 1, 2, 4, 4, 4, 7, 8, 8]

y, idx = unique(x) y ==> [1, 2, 4, 7, 8] idx ==> [0, 0, 1, 2, 2, 2, 3, 4, 4] ```

Arguments:

  • scope: A Scope object
  • x: 1-D.

Returns:

Constructors and Destructors

Unique(const ::tensorflow::Scope & scope, ::tensorflow::Input x)
Unique(const ::tensorflow::Scope & scope, ::tensorflow::Input x, const Unique::Attrs & attrs)

Public attributes

idx
y

Public static functions

OutIdx(DataType x)

Structs

tensorflow::ops::Unique::Attrs

Optional attribute setters for Unique.

Public attributes

idx

::tensorflow::Output idx

y

::tensorflow::Output y

Public functions

Unique

 Unique(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x
)

Unique

 Unique(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x,
  const Unique::Attrs & attrs
)

Public static functions

OutIdx

Attrs OutIdx(
  DataType x
)