tensorflow::ops::ConjugateTranspose

#include <array_ops.h>

Shuffle dimensions of x according to a permutation and conjugate the result.

Summary

The output y has the same rank as x. The shapes of x and y satisfy: y.shape[i] == x.shape[perm[i]] for i in [0, 1, ..., rank(x) - 1]y[i,j,k,...,s,t,u] == conj(x[perm[i], perm[j], perm[k],...,perm[s], perm[t], perm[u]])

Arguments:

Returns:

Constructors and Destructors

ConjugateTranspose(const ::tensorflow::Scope & scope, ::tensorflow::Input x, ::tensorflow::Input perm)

Public attributes

y

Public functions

node() const
::tensorflow::Node *
operator::tensorflow::Input() const
operator::tensorflow::Output() const

Public attributes

y

::tensorflow::Output y

Public functions

ConjugateTranspose

 ConjugateTranspose(
  const ::tensorflow::Scope & scope,
  ::tensorflow::Input x,
  ::tensorflow::Input perm
)

node

::tensorflow::Node * node() const 

operator::tensorflow::Input

 operator::tensorflow::Input() const 

operator::tensorflow::Output

 operator::tensorflow::Output() const