SetDiff1d
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Computes the difference between two lists of numbers or strings.
Given a list `x` and a list `y`, this operation returns a list `out` that
represents all values that are in `x` but not in `y`. The returned list `out`
is sorted in the same order that the numbers appear in `x` (duplicates are
preserved). This operation also returns a list `idx` that represents the
position of each `out` element in `x`. In other words:
`out[i] = x[idx[i]] for i in [0, 1, ..., len(out) - 1]`
For example, given this input:
x = [1, 2, 3, 4, 5, 6]
y = [1, 3, 5]
This operation would return:
out ==> [2, 4, 6]
idx ==> [1, 3, 5]
Inherited Methods
From class
java.lang.Object
boolean
|
equals(Object arg0)
|
final
Class<?>
|
getClass()
|
int
|
hashCode()
|
final
void
|
notify()
|
final
void
|
notifyAll()
|
String
|
toString()
|
final
void
|
wait(long arg0, int arg1)
|
final
void
|
wait(long arg0)
|
final
void
|
wait()
|
Public Methods
public
static
SetDiff1d<T, U>
create
(Scope scope, Operand<T> x, Operand<T> y, Class<U> outIdx)
Factory method to create a class wrapping a new SetDiff1d operation.
Parameters
scope |
current scope |
x |
1-D. Values to keep. |
y |
1-D. Values to remove. |
Returns
- a new instance of SetDiff1d
Factory method to create a class wrapping a new SetDiff1d operation using default output types.
Parameters
scope |
current scope |
x |
1-D. Values to keep. |
y |
1-D. Values to remove. |
Returns
- a new instance of SetDiff1d
public
Output<U>
idx
()
1-D. Positions of `x` values preserved in `out`.
public
Output<T>
out
()
1-D. Values present in `x` but not in `y`.
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Last updated 2022-10-27 UTC.
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