TensorFlow 1 version | View source on GitHub |
Computes tf.math.logical_or
of elements across dimensions of a tensor.
tf.math.reduce_any(
input_tensor, axis=None, keepdims=False, name=None
)
This is the reduction operation for the elementwise tf.math.logical_or
op.
Reduces input_tensor
along the dimensions given in axis
.
Unless keepdims
is true, the rank of the tensor is reduced by 1 for each
of the entries in axis
, which must be unique. If keepdims
is true, the
reduced dimensions are retained with length 1.
If axis
is None, all dimensions are reduced, and a
tensor with a single element is returned.
For example:
x = tf.constant([[True, True], [False, False]])
tf.reduce_any(x)
<tf.Tensor: shape=(), dtype=bool, numpy=True>
tf.reduce_any(x, 0)
<tf.Tensor: shape=(2,), dtype=bool, numpy=array([ True, True])>
tf.reduce_any(x, 1)
<tf.Tensor: shape=(2,), dtype=bool, numpy=array([ True, False])>
Args | |
---|---|
input_tensor
|
The boolean tensor to reduce. |
axis
|
The dimensions to reduce. If None (the default), reduces all
dimensions. Must be in the range [-rank(input_tensor),
rank(input_tensor)) .
|
keepdims
|
If true, retains reduced dimensions with length 1. |
name
|
A name for the operation (optional). |
Returns | |
---|---|
The reduced tensor. |
numpy compatibility
Equivalent to np.any