tfm.optimization.math.hypot

hypot(*coordinates) -> value

Multidimensional Euclidean distance from the origin to a point.

sqrt(sum(x**2 for x in coordinates))

For a two dimensional point (x, y), gives the hypotenuse using the Pythagorean theorem: sqrt(xx + yy).

For example, the hypotenuse of a 3/4/5 right triangle is:

<pre class="devsite-click-to-copy prettyprint lang-py">
<code class="devsite-terminal" data-terminal-prefix="&gt;&gt;&gt;">hypot(3.0, 4.0)</code>
<code class="no-select nocode">    5.0</code>
<code class="no-select nocode">    </code>
</pre>