Save the date! Google I/O returns May 18-20

# tf.math.unsorted_segment_sqrt_n

Computes the sum along segments of a tensor divided by the sqrt(N).

Read the section on segmentation for an explanation of segments.

This operator is similar to the tf.math.unsorted_segment_sum operator. Additionally to computing the sum over segments, it divides the results by sqrt(N).

$$output_i = 1/sqrt(N_i) \sum_{j...} data[j...]$$ where the sum is over tuples j... such that segment_ids[j...] == i with \N_i\ being the number of occurrences of id \i\.

If there is no entry for a given segment ID i, it outputs 0.

Note that this op only supports floating point and complex dtypes, due to tf.sqrt only supporting these types.

If the given segment ID i is negative, the value is dropped and will not be added to the sum of the segment.

data A Tensor with floating point or complex dtype.
segment_ids An integer tensor whose shape is a prefix of data.shape.
num_segments An integer scalar Tensor. The number of distinct segment IDs.
name A name for the operation (optional).

A Tensor. Has same shape as data, except for the first segment_ids.rank dimensions, which are replaced with a single dimension which has size num_segments.

[{ "type": "thumb-down", "id": "missingTheInformationINeed", "label":"Missing the information I need" },{ "type": "thumb-down", "id": "tooComplicatedTooManySteps", "label":"Too complicated / too many steps" },{ "type": "thumb-down", "id": "outOfDate", "label":"Out of date" },{ "type": "thumb-down", "id": "samplesCodeIssue", "label":"Samples / code issue" },{ "type": "thumb-down", "id": "otherDown", "label":"Other" }]
[{ "type": "thumb-up", "id": "easyToUnderstand", "label":"Easy to understand" },{ "type": "thumb-up", "id": "solvedMyProblem", "label":"Solved my problem" },{ "type": "thumb-up", "id": "otherUp", "label":"Other" }]